看板 R_Language 關於我們 聯絡資訊
*[m- 問題: 當你想要問問題時,請使用這個類別。 建議先到 http://tinyurl.com/mnerchs 搜尋本板舊文。 [問題類型]: 效能諮詢(我想讓R 跑更快) [軟體熟悉度]: 使用者(已經有用R 做過不少作品) [問題敘述]: 大家好 我的資料是紀錄籃球比賽每個play是哪5個進攻及防守球員在場上 想做的事情是: 假設總共有500位球員 做出一個n(750000) x p(1000)的矩陣 前500欄為進攻 後500欄為防守 矩陣內的元素為1代表球員在場上進攻(防守為-1) 不在場上為0 所以每列會有5個1及5個-1還有很多個0 資料大概長這樣 data$p.combination data$p.com.allowed 1 A, B, C, D, E J, K, L, M, N 2 A, C, F, H, I K, L, M, N, O 3 C, D, X, Y, Z K, M, O, Q, R ... ... ... 人名之間是用逗號和一個空格分開 用我自己寫的已經跑了快12小時還沒跑完 想請教版上各位大大有沒有更好的寫法 [程式範例]: https://ideone.com/PaBtM4 library(magrittr) p.combination = character(1000) for(i in 1:length(p.combination)){ p.combination[i] = LETTERS[sample(1:26,5)] %>% paste0(collapse = ", ") } p.com.allowed = character(1000) for(i in 1:length(p.com.allowed)){ p.com.allowed[i] = LETTERS[sample(1:26,5)] %>% paste0(collapse = ", ") } data = data.frame(p.combination = p.combination, p.com.allowed = p.com.allowed) player = LETTERS[1:26] input.matrix0 = function(data, player, off){ X = matrix(ncol = length(player), nrow = dim(data)[1]) for(i in 1:dim(data)[1]){ if(off) { colnames(X) = paste0("O_",player) coding = 1 pp = data$p.combination } else { colnames(X) = paste0("D_",player) coding = -1 pp = data$p.com.allowed } player.temp = pp[i] %>% gsub(", ", "|",.) index = grep(player.temp, player) X[i,index] = coding X[i,-index] = 0 } return(X) } input.matrix = function(data, player){ X.off = input.matrix0(data, player, T) X.def = input.matrix0(data, player, F) return(cbind(X.off, X.def)) } out = input.matrix(data,player) -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 58.114.236.110 ※ 文章網址: https://www.ptt.cc/bbs/R_Language/M.1514527291.A.C47.html