推 henryfy:帥氣喔 程式都出來了~~~~ 01/13 13:53
推 ray110411:學類比ic的 懶得看～ 01/13 13:53
推 delete0623:cool~ 01/13 13:53
→ carlcarl:現在重點變成對題意理解不同 所以用程式跑可能沒意義.. 01/13 13:56
→ erotic:把問題複雜化，先fire再說 = = 01/13 14:24
不知道可不可以這樣解...
int children[2]; // 1 is boy and 0 is girl
// children[0] is elder, children[1] is younger
int firstseeisboycount = 0;
int secondseeisboycount = 0;
randomize();
for(int i=0;i<10000;i++){
children[0]=rand()%2;
children[1]=rand()%2;
int firstseeindex = rand()%2; // firstsee is elder or younger
if(children[firstseeindex]==1){
// 1st see is boy
firstseeisboycount++;
if(firstseeindex==0){
if(children[1]==1){
secondseeisboycount++;
}
}
else{
if(children[0]==1){
secondseeisboycount++;
}
}
}
}
所以機率就是 secondseeisboycount/firstseeisboycount ~= 1/2
這樣對嗎?
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