推 lumiya:這大題的三小題，優良推定量條件，算族群大小～ 01/12 19:17
→ lumiya:小樣本的區間推定，變異數的區間推定，E of conft.Inval. 01/12 19:19
→ lumiya:兩母體均數差，母體比例差 please at least repeat 3 ti. 01/12 19:22
→ lumiya:wish a good final, good luck 01/12 19:23
Sandy幫大家準備的複習考裡面的第九題第二小題的答案有更正！
更正為 [(S1^2)x(σ2^2)]/[(S2^2)*(σ1^2)]
= [(S1^2)/(σ1^2)]*[(σ2^2)/(S2^2)]
= (χ1^2)*[1/(χ2^2)]
= (χ1^2)/(χ2^2)
= F(n1,n2)
大家請參考～
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