[問題] 關於POST該輸入的參數

[senjor (哞哞)]

小弟今天要對一個網頁傳送POST
利用fiddler抓到TEXTVIEW如下
-----------------------------7d719c1f806fa
Content-Disposition: form-data; name="configfile"

/usr/opt/www/pub/CBS/services/NetPhos-2.0/NetPhos.cf
-----------------------------7d719c1f806fa
Content-Disposition: form-data; name="SEQPASTE"

<KLVDTANFDDYMKALGVGFATRQMAGLTKEISFKLDEEFDETTADDRHVKKLILTLTMGNVVSTRTYPTTI
-----------------------------7d719c1f806fa
Content-Disposition: form-data; name="SEQSUB"; filename=""
Content-Type: application/octet-stream

那我程式碼如下
HttpWebRequest myHttpWebRequest =
(HttpWebRequest)WebRequest.Create("http://www.cbs.dtu.dk/services/NetPhos/");

            myHttpWebRequest.Method = "POST";

            string postData =
"-----------------------------7d732224806fa\nContent-Disposition: form-data;
name=\"configfile\"\n\n/usr/opt/www/pub/CBS/services/NetPhos-2.0/NetPhos.cf\n-----------------------------7d732224806fa\nContent-Disposition:
form-data;
name=\"SEQPASTE\"\n<KLVDTANFDDYMKALGVGFATRQMAGLTKEISFKLDEEFDETTADDRHVKKLILTLTMGNVVSTRTYPTTI\n-----------------------------7d732224806fa\nContent-Disposition:
form-data; name=\"SEQSUB\"; filename=\"\"\nContent-Type:
application/octet-stream";
            ASCIIEncoding encoding = new ASCIIEncoding();
            byte[] byte1 = encoding.GetBytes(postData);

            myHttpWebRequest.ContentType = "multipart/form-data";

            myHttpWebRequest.ContentLength = byte1.Length;

            Stream newStream = myHttpWebRequest.GetRequestStream();

            newStream.Write(byte1, 0, byte1.Length);
            MessageBox.Show("The value of 'ContentLength' property after
sending the data is "+ myHttpWebRequest.ContentLength);

            newStream.Close();

            HttpWebResponse myResp =
(HttpWebResponse)myHttpWebRequest.GetResponse();
            StreamReader myReader = new
StreamReader(myResp.GetResponseStream());

            webBrowser1.DocumentText = myReader.ReadToEnd();

其實我不確定的是
POSTDATA裡面到底要裝什麼
要怎麼表達我要傳送的變數名稱跟內容呢

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推 seagal:Post裡面裝的應該是name=value的pair
→ seagal:ex. SEQPASTE=XXXXX
推 ddavid:Name1=Val1&Name2=Val2&Name3=Val3這樣
→ ddavid:你需要讀下來之後自己再用程式去把它一個個分離
→ ddavid:同時像空白之類會被轉換掉的特殊字元你也要自行還原
推 senjor:我知道了！因為MSDN都沒有格式解說，感謝樓上兩位大大 XD