Re: [問題] 撲克牌牌組判斷

[enthos (影斯)]

※ 引述《jason06184 (講座)》之銘言：
: 簡單來說我跑出來要是像這樣的東西
:  4 of Hearts
:  7 of Diamonds
:  4 of Diamonds
:  7 of Clubs
:  7 of Spades
: 這副牌為7葫蘆

// 32-bit, linux
#include <stdio.h>
#include <stdlib.h>

/* initialize suit array */
const char *suit[ 4 ] = { "Hearts", "Diamonds", "Clubs", "Spades" };

/* initialize face array */
const char *face[ 13 ] =
{ "ACE", "2", "3", "4",
"5", "6", "7", "8",
"9", "10", "Jack", "Queen", "King" };

// card is 0 ... 51
void show_card(int card)
{
  if (card < 0 || card > 51)
    perror("Error.");
  printf("%s of %s.\n", face[card % 13], suit[card / 13]);
}

void check_fullhouse(int a, int b, int c, int d, int e)
{
  int *tmp;
  int i;
  int flag_2 = 0; int flag_3 = 0;
  int fullhouse_card = 0;
  tmp = calloc(14, sizeof(int));
  tmp[a % 13]++;
  tmp[b % 13]++;
  tmp[c % 13]++;
  tmp[d % 13]++;
  tmp[e % 13]++;
  for(i = 0; i <= 12; i++) {
    if (tmp[i] == 2)
      flag_2++;
    if (tmp[i] == 3) {
      flag_3++;
      fullhouse_card = i;
    }
  }
  if (flag_2 == 1 && flag_3 == 1)
    printf("這副牌為%s葫蘆\n", face[fullhouse_card]);
  else
    printf("Bad cards.\n");
  free(tmp);
}

int main()
{
  show_card(3); show_card(6 + 13); show_card(3 + 13);
  show_card(6 + 26); show_card(6 + 39);
  check_fullhouse(3, 19, 16, 32, 45);
  check_fullhouse(1, 8, 9, 11, 22);
  return 0;
}

/*
 user@linux$ gcc -o card.bin card.c
 user@linux$ ./card.bin
 4 of Hearts.
 7 of Diamonds.
 4 of Diamonds.
 7 of Clubs.
 7 of Spades.
 這副牌為7葫蘆
 Bad cards.
*/


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◆ From: 140.113.22.98
→ jason06184:似乎有瑕疵
推 loveflames:你不是要葫蘆的判定方法嗎?還是說沒照原本程式格式寫就
→ loveflames:叫有瑕疵?
推 jason06184:不是  我的意思不是這樣 我的意思是放進去跑有錯誤
→ game0416:這不是你自己的問題嗎...?
推 jason06184:原來如此  我稍稍改一下下
→ siuol:tmp = (int *)calloc(size_t, size_t);
→ siuol:原PO應該不會強制轉型態吧....
推 jason06184:樓上的ID..=口=!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
→ james732:用 gcc 沒寫 (int *) 其實沒關係...XD