Re: [問題] ACM 382 Perfection WA

[Powernow (PowerNow!)]

這題還蠻簡單的呀，隨便寫了一個就過了 :)

#include <stdio.h>

char ResultPerfect[] = {"PERFECT"};
char ResultDeficient[] = {"DEFICIENT"};
char ResultAbundant[] = {"ABUNDANT"};

char *CheckResult(int Value)
{
    int start, sum = 0;

    for (start = 1; start < Value; start++)
        sum += (0 == (Value % start) ? start : 0);

    if (sum == Value) return ResultPerfect;
    if (sum < Value) return ResultDeficient;
    return ResultAbundant;
}

int main(int argc, char *argv[])
{
    int i, buf[100];

    for (i = 0; 1 == scanf("%d", &buf[i]); i++)
        if (0 == buf[i]) break;

    printf("PERFECTION OUTPUT\n");
    for (i = 0; 0 != buf[i]; i++)
        printf("%*d  %s\n", 5, buf[i], CheckResult(buf[i]));
    printf("END OF OUTPUT\n");

    return 0;
}

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