[問題] FFT程式碼問題

[psallen (psallen)]

小弟是C++新手，最近需要用到快速傅立葉轉換(FFT)，上網google後有找到

以下的程式碼，但在Debug的時候在最後一行return(TRUE)顯示出

IntelliSense: 識別項 "True" 未定義，請問該如何修改?先謝謝大家了。

/*
   This computes an in-place complex-to-complex FFT
   x and y are the real and imaginary arrays of 2^m points.
   dir =  1 gives forward transform
   dir = -1 gives reverse transform
*/
short FFT(short int dir,long m,double *x,double *y)
{
   long n,i,i1,j,k,i2,l,l1,l2;
   double c1,c2,tx,ty,t1,t2,u1,u2,z;

   /* Calculate the number of points */
   n = 1;
   for (i=0;i<m;i++)
      n *= 2;

   /* Do the bit reversal */
   i2 = n >> 1;
   j = 0;
   for (i=0;i<n-1;i++) {
      if (i < j) {
         tx = x[i];
         ty = y[i];
         x[i] = x[j];
         y[i] = y[j];
         x[j] = tx;
         y[j] = ty;
      }
      k = i2;
      while (k <= j) {
         j -= k;
         k >>= 1;
      }
      j += k;
   }

   /* Compute the FFT */
   c1 = -1.0;
   c2 = 0.0;
   l2 = 1;
   for (l=0;l<m;l++) {
      l1 = l2;
      l2 <<= 1;
      u1 = 1.0;
      u2 = 0.0;
      for (j=0;j<l1;j++) {
         for (i=j;i<n;i+=l2) {
            i1 = i + l1;
            t1 = u1 * x[i1] - u2 * y[i1];
            t2 = u1 * y[i1] + u2 * x[i1];
            x[i1] = x[i] - t1;
            y[i1] = y[i] - t2;
            x[i] += t1;
            y[i] += t2;
         }
         z =  u1 * c1 - u2 * c2;
         u2 = u1 * c2 + u2 * c1;
         u1 = z;
      }
      c2 = sqrt((1.0 - c1) / 2.0);
      if (dir == 1)
         c2 = -c2;
      c1 = sqrt((1.0 + c1) / 2.0);
   }

   /* Scaling for forward transform */
   if (dir == 1) {
      for (i=0;i<n;i++) {
         x[i] /= n;
         y[i] /= n;
      }
   }

   return(TRUE);
}



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◆ From: 140.116.75.201
※ 編輯: psallen         來自: 140.116.75.201       (01/06 15:18)
推 ericinttu:你覺得 TRUE 是什麼東西?
→ ericinttu:就程式結構而言,不知道要return給caller有什麼做用?
→ psallen:我也不太清楚那個意思，我刪掉RETURN那行後他會顯示
→ psallen:FFT需要傳回值
推 ericinttu:可以查一下C/C++的書或網路資料,找"副程式"跟"回傳值"
→ psallen:OK我查查看 感謝
→ fuha:真的 沒有了