作者killyou (xxx)
看板Chang_Course
標題[習題] 1.13 (b)似乎不完整
時間Wed Nov 7 15:51:03 2007
the answer: _
G P4-free, both G, G connected with min n(G)
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G-v P4-free, so one of G-v and G-v is disconnected
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if G_v disconnceted, then v isolated in G......#
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可是還有一個case: 要是 G-v connected 當然 G-v disconnected.
ex: C4
join
或許你可以假設 G-v= ▽ G_i, then
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1. v 至少會連到一個 component of G-v,since G connected
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2. 而且每個G_i都會有一點不連到v, since G connceted
再由此去找出P4, 得到矛盾.
p.s.我的做法是證明:
If G connctedand P4-free, then G is a complete bipartite graph.
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◆ From: 140.112.231.114
推 over:那是在不失一般性情況下的假設,你說的case 140.112.50.174 11/08 02:13
推 over:也可以reduce成這種! 140.112.50.174 11/08 02:14
→ killyou:\bar{G-v}=\bar{G}-v,這樣WLOG比較順吧?140.112.231.114 11/08 22:47
推 over:嗯嗯對! 140.112.50.238 11/09 23:40
推 ugoc:P4是自反同構,這樣G若是P4-free那G-bar也是 61.31.133.126 11/10 01:02