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the answer: _ G P4-free, both G, G connected with min n(G) ___ G-v P4-free, so one of G-v and G-v is disconnected _ if G_v disconnceted, then v isolated in G......# ___ 可是還有一個case: 要是 G-v connected 當然 G-v disconnected. ex: C4 join 或許你可以假設 G-v= ▽ G_i, then ___ 1. v 至少會連到一個 component of G-v,since G connected _ 2. 而且每個G_i都會有一點不連到v, since G connceted 再由此去找出P4, 得到矛盾. p.s.我的做法是證明: If G connctedand P4-free, then G is a complete bipartite graph. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.231.114
over:那是在不失一般性情況下的假設,你說的case 140.112.50.174 11/08 02:13
over:也可以reduce成這種! 140.112.50.174 11/08 02:14
killyou:\bar{G-v}=\bar{G}-v,這樣WLOG比較順吧?140.112.231.114 11/08 22:47
over:嗯嗯對! 140.112.50.238 11/09 23:40
ugoc:P4是自反同構,這樣G若是P4-free那G-bar也是 61.31.133.126 11/10 01:02