[問題] newOp.cpp的問題

[suspect1 (嫌犯)]

  Dear All:

      在這個範例中，若  A* b = new A[10]; 在main中傳回來的位址是

 b = 10*sizeof(A)+4 ; 其中多出的四個 BYTE 是用來存放 10 的嗎？

  可是我用 cout << *b << endl; 看到的卻是亂碼，請問我錯在哪？

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推 ric2k1:Please print out *(address(b) - 4)...
→ ric2k1:I don't mean "cout << *(address(b) - 4) << endl;
→ ric2k1:Please figure out a way to print it!
推 suspect1:再給點提示嗎？我用了*(size_of(b)-4)編譯不過
→ suspect1:打錯了＠＠  *(size_t(b)-4)
推 ric2k1:size_t(b) ==> becomes a size_t variable
→ ric2k1:size_t(b) - 4 ==> the "content" of (size_t(b)) - 4
→ ric2k1:size_t(b) - 4 ==> still a size_t type variable
→ ric2k1:*(size_t(b) - 4) ==> (size_t(b) - 4) is NOT a pointer
→ ric2k1:That's why you have compilation error
→ ric2k1:Try to start with (size_t*)b.... that's all I can say.
→ ric2k1:More question, please see me in person...
推 suspect1:謝謝老師～終於對了！
推 ric2k1::)