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[IamYGO (Near)]

A carnot engine extracts 240J from its high-temperature reservoir during each

cycle, and rejects 100J to the environment at 15度c

*1.What is its efficiency?

*2.What is the temperature of the hot reservoir



有解答後自d

謝謝

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推 kblover:普物詳解愛你
推 blueskydgdg:我想是每240J會有100J散失所以轉換效率是
→ blueskydgdg:(140/240)*100趴先=58.3趴
→ blueskydgdg:第二題我猜是求熱容，可是我不知道公式
→ blueskydgdg:有錯請鞭小力一點\= =
推 newsboy3423:http://cid-f65c293ed7906cf3.skydrive.live.com/brow
→ newsboy3423:等等 上面網址好像連不到   囧
推 target8917:卡諾熱機有好用特性 課本有
推 KOBEDIRK:e= 1 - T(H)/T(L)
推 KOBEDIRK:又e = [Q(H)-Q(L)]/Q(H)
→ KOBEDIRK:1 - T(H)/T(L) = [Q(H)-Q(L)]/Q(H)
→ KOBEDIRK:1 - T(H)/(273+15) = [240-100]/240  得解
→ KOBEDIRK:應該是這樣啦=   =   錯了來訐我
推 KOBEDIRK:挖勒錯了 1 - (273+15)/T(H) = [240-100]/240  得解
→ KOBEDIRK:前四個式子 T(H) 跟 T(L) 的位置要掉換才對 樓上是對的
→ KOBEDIRK:關鍵字是 carnot engine,其實課本有些關於他的公式
→ IamYGO:感謝