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※ 引述《aaaaaf (kkman)》之銘言: : ※ 引述《Rigid (陽光下的奇蹟)》之銘言: : : 乘吧? : : 假設0.7V一個diode turn on的話 : : 串連應該會要兩倍電壓 : : 所以應該是1.4V turn on : : 應該是要乘二吧? : : 還是我想錯了? XD : 因為電壓源為1.5Vr : 兩個串聯二極體導通 : 故每個為0.75Vr : 分壓加起來=電壓源為1.5Vr : 只是我第二個二極體負載線不會劃 : 可以教我嗎 : 感恩 ok, I see My answer is just for the I-V curve of two diodes. If you want to get a load-line of these two diodes in a specific applied voltage, you should do somethings: 1. replot the I-V curve of diode with (1.5 Vr-V) as the x axis 2. put the original curve of diode with the replotted one 3. the intersection is the answer -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.113.195.37
l1l1l1l1:英文真好 05/28 00:50
Rigid:no, i still made some mistakes 'at applied voltage' XD 05/28 00:54