Dag-Erling Sm鷨grav wrote:
>Don Dugger <dugger@hotlz.com> writes:
>
>
>>Dag-Erling Sm鷨grav <des@des.no> writes:
>>
>>
>>>Don Dugger <dugger@hotlz.com> writes:
>>>
>>>
>>>>The fact is that all your c code will compile in c++
>>>>
>>>>
>>>That is wrong. To name just one example, C++ is much stricter about
>>>type casts than C is.
>>>
>>>
>>I mean the constructs. Casting will not change the functionality or
>>shouldn't.
>>
>>
>
>It does. Casting can be (and often is) used to force or avoid sign
>promotion in function arguments; for instance, isspace(ch) may produce
>incorrect results if ch is a char, so a cast to int is required.
>
>C allows any expression of pointer type to be assigned to a void *,
>and allows any expression of type void * to be assigned to any object
>pointer type. C++ does not. As a result, a typical C program which
>uses malloc() without casting the result will not compile cleanly with
>a C++ compiler. A competent C programmer will balk at adding the cast
>that C++ requires; a competent C++ programmer will correctly point out
>that a C++ program should not use malloc() anyway.
>
>There are other incompatiblities: const has different semantics in C
>and C++, namespaces aren't quite the same (there is no separation
>between the typedef namespace and the struct namespace in C++), etc.
>
>DES
>
>
And how does that change my point?
Don 8)
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