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On Friday, August 05, 2011 10:08:27 am Christoph Hoffmann wrote: > Hello Everyone, >=20 > Despite the BIOS information about the nonexistent floppy, the zfsboot.c= =20 code=20 > will prevent to boot from the first HDD if a floppy is given as a first=20 available device. >=20 > The drive 0x0 (floppy) will be probed before the code below and an error= =20 occurs: > [=85] > gptzfsboot: error 1 lba 32 = =20 > gptzfsboot: error 1 lba 1 = =20 > [=85] >=20 > The continue statement will skip the rest of the iteration because =20 > if ((i | DRV_HARD) =3D=3D *(uint8_t *)PTOV(ARGS))=20 > is true if the drive equals 0x80. As a result we do not call probe_drive() > for this drive. But that shouldn't happen if ARGS has a drive number of 0. (In that case 0= x80=20 !=3D 0x0, so it shouldn't match.) This shows that PTOV(ARGS) actually has a %dl value of 0x80 which is correc= t. =20 The question is how your initial 'dsk' ended up using 0x0 instead of 0x80. Note that your 'type' is 0, so that means that it was ok initially (TYPE_AD= is=20 0): dsk->drive =3D *(uint8_t *)PTOV(ARGS); dsk->type =3D dsk->drive & DRV_HARD ? TYPE_AD : TYPE_FD; Somewhere between where 'dsk' is initalized in main() and before probe_driv= e()=20 is called in main() for 'dsk', 'dsk->drive' is getting clobbered. Can you = add=20 some additional printfs to nail down where that is happening? =2D-=20 John Baldwin _______________________________________________ freebsd-current@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-current To unsubscribe, send any mail to "freebsd-current-unsubscribe@freebsd.org"