Re: [機經] 11月JJ-205 MATH

[cbrf (人品)]

※ 引述《a2515125 (Bobshih)》之銘言：
: x,y皆>0，問 y/(x^(1/2))+(x^(1/2))/x 為多少?
: JJ: (y+1)/(x^(1/2))
: 想請教如何變的

[y/x^(1/2)] + [x^(1/2)/x]
=[y*x^(1/2)/x] + [x^(1/2)/x]
=x^(1/2)(y+1)/x
=(y+1)/x^(1/2)

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