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Machines X and Y work at their respective constant rates. How many more hours does it take machine Y, working alone, to fill a production order of a certain size than it takes machine X, working alone? (1) Machines X and Y, working together, fill a production order of this size in two-thirds the time that machine X, working alone, does. (2) Machine Y, working alone, fills a production order of this size in twice the time that machine X, working alone, does. (解) 設work=1, machineX=Xhour, machineY=Yhour, 問y-x=? (1) 1/X + 1/Y = 2/3 ^ 1/X (2) 1/Y = 2^ 1/X 答案是E 可是直覺上兩個變數,配上兩條式子,為什麼不是C ?tt.cc) ◆ From: 60.245.105.187
pei33ho:太神了 正要發問這題 以為自己眼花怎麼PO好了! 想要順便問 11/19 21:16
pei33ho:第二個算式表達對嗎? 感覺是1/X=2*1/Y ? 誰能回答一下~謝 11/19 21:18
pei33ho:原PO符號寫錯 次方符號應該是乘號吧!!! 11/19 21:20
clearfuture:歹勢....第一次PO.....SORRY 11/20 10:43