If 2 different representatives are to be selected at random from a group of
10 employees and if p is the probability that both representatives selected
will be women, is p > 1/2?
(1) More than 1/2 of the 10 employees are women.
(2) The probability that both representatives selected will be men is less
than 1/10.
答案是E
(1) 我知道女性至少6個, 所以P= C(6,2) / C(10,2) = 1/3 -->insufficient
請問(2)該如何解呢?
謝謝!
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