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※ 引述《loeooo (籃球狂)》之銘言: : 1. how many solutions are there to the equation X1+X2+X3+X4+X5=21, : where Xi, i=1,2,3,4,5 is a nonnegative integer such that 0<=Xi<=10 : 求整數解個數跟求非負整數解個數一樣嗎? 求整數解我會 : 但求非負要怎麼求阿? 這是用生成函數解法 每個X的生成函數(1+X^1+X^2+...+X^10) 五個就是(1+X^1+...+X^10)^5 最後求X^21的係數 : 2. There are _________ consecutive 0s at the end of the binary expansion : of 70! : 3. there are ________4-digit decimal telephone numbers haviing one or : more repeated digits. : 4. if there are five possible grades, A,B,C,D,and F, the minimum number of : students required in a class to be sure that at least six will receive the : same grade is ________________. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 122.117.186.227