推 lu1227:感謝你的回答><~~ 03/27 00:14
※ 引述《lu1227 (lu)》之銘言：
: 題目:Suppose that a certain software product has a mean time
: beteween failures of 10,000 hours and has a mean time to
: repair of 20 hours. If the product is used by 100 customers,
: what is ites availability?
: 1)80.2%
: 2)90.1%
: 3)98.9%
: 4)99.8%
: 5)100%
: 我在網路上也找不到算法~麻煩各位了~感溫~~
網路上很難找而已...話說我臨時抱佛腳(應該沒啥用
Availability = MTBF/(MTBF+MTTR)
MTBF: mean time between failure
MTTR: mean time to repair
Availability = 10,000/(10,000+20) = 0.998---------(D)
MTBF: 10,000
MTTR: 20
100人 就 不知道有什麼用?(又有分並連串聯的
資料據說是來自CCDP思科...
有錯請指證~^ ^
--
╭╩╦╩╦╩╦╩╦╩╦╩╦ ☆ ╩╦╩╦╩╦ ★ ╩╦╮
║ ◢■■◣ ■ ■ ● ║
║ ■ ■ ■ ■ ◢■◣ ★ ║
║ ■ ■ ■ ■ ■ ■ ■ ☆ ║
║ ◥■■◤ ■ ■ ■ ■ ■ ║
╰ ★ ╦╩╦╩╦╩╦╩╦╩╦╩╦~ Only in My Mind ~╯
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 61.66.73.56