Assume a microprocessor has 20-bit address bus and 16-bit data bus.
The memory utilization involves 64K byte for I/O device,
64K byte for EPROM device, and other for SRAM.
How many SRAM devices of size 64K*8 are required in such a microprocessor?
我想問的是這個microprocessor的容量是多少?
我覺得應該是 2^位址線*資料線
= 2^20*16 (bit) 再除以8 bit 變成byte
可是我看了高銘寫的解答 卻是
2^位址線 * 8 bit = 2^20(byte)
讓我搞混了 他的8-bit是哪裡來的阿?
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 125.224.102.30