推 hsiehdler:先同除N!=>2/N! = 1/(N-1)!T(N-1)+3 04/16 00:08
→ hsiehdler:令F(N)=N!T(N)=> 2F(N)=F(N-1)+3 解之 04/16 00:10
Use a summation factor to solve the recurrence
T0 = 5
2Tn = nT(n-1) + 3*n! , for n > 0
麻煩各位幫幫忙^^
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