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1.Please find the solution of ordinary differential equation (x^2+1)y''-2xy'+2y=6(x^2+1)^2 Boundary condition y(x=0)=-1,y(x=1)=5 2.Given an ordinary differential equation as d^2y dy x------ + 2(x-1)------- +(x-2)y=0 dx^2 dx If boundary condition is given as y(0)=y0,solve for y(x). 先謝謝大家囉,變係數實在沒有頭緒.. -- ▼▼▼▼ ▲▲▲▲ < | | -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.41.140.72
SONGya168:請修改標題囉 06/01 23:03
littleyinyo:修改好了,抱歉造成版主困擾!! 06/02 00:33
SONGya168:還要空一格半形唷 XD 我幫你移好了XDD 06/02 00:40
littleyinyo:謝謝版主:) 06/02 00:53