→ iyenn:1. m1=4x/3 m1*m2=-1 正交軌跡 dy/dx=m2 07/19 23:02
→ iyenn:dy/dx = -3/4x => 3dx+4xdy=0 => 3/x dx+ 4dy=0 正合 07/19 23:04
→ iyenn:3ln(x)+4y=c' =>x^3 * e^(4y)=c ok~ 07/19 23:05
1.F(x, y ,k)= 2x^2-3y-k= 0
asn: x^3 e^(4y)= c
2.(1+x^2)y^2-2xy= 1+x^2 , y(0)=1
ans: x= tan(y/(x^2+1)-1)
3.y= 4x+1+ce^4x 與正交軌跡通過點(0, 0)
ans:x-y/4=(1-e^(16y))/64
有請高手~!
謝謝
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