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y'={2(xy^1/2)-y}/x ans= y^1/2=x^1/2{1-(1/cx)} 解不出來 = =...幫幫忙 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.229.202.15
becomesonumb:是根號XY 還是根號Y ? 09/27 13:59
wellilin:(XY)^1/2 09/27 14:01
hsuan0425:Bernoulli ODE 09/27 14:53