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※ 引述《AAJJBurnett (叫我投手)》之銘言: : A store sells four brands of VCRs.The least expensive brand B1 accounts : for 40% of the sales. The other brands(in order of their price) have the : following percentages of sales:B2,30%;B3,20%;and B4,10%.The respective : probabilities of needing repair during warranty are 0.10 for B1,0.05 for : B2, 0.03 for B3, and 0.02 for B4. A randomly selected purchaser has a VCR : that needed repair under warranty. What are the four conditional : probabilities of being brand Bi, i=1,2,3,4 ? 令Y為送修事件 0.10, i=1 0.05, i=2 P(Y|Bi)= 0.03, i=3 0.02, i=4 0.4, i=1 0.3, i=2 且P(Bi)= 0.2, i=3 0.1, i=4 可依序得,P(Y╭╮B1)=0.10*0.4=0.04 ...etc 將得到的四個機率總合,可得到P(Y) 而  P(Y╭╮B1) ------------ = P(B1|Y)....此求法得依序得其它條件機率。 P(Y) 有錯請指教, 謝謝~  -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 123.193.74.12
AAJJBurnett:3Q~ 10/06 10:26