※ 引述《kk0622 (kk)》之銘言：
: A gas designated by subscript 1,is to be dissolved in a nonvolatile liquid.
: At a certain pressure and temperature the solubility of the gas in the liquid
: is X1 (X is mole fraction).Assume that Henry's law holds.Show that the change
: in solubility with temperature is given by
: d(lnX1)/d(1/T) = -△h/R
: where △h=h(in liquid solution)-h(pure gas)
: at the same pressure and temperature.On the basis of physical reasoning alone,
: would you expect △h to be positive or negative?
: 請各位高手幫忙解答一下 謝謝
d(lnX1)/d(1/T) = -△h/R
積分之後
-△h = RTlnX1
很明顯的這個混和性質是屬於吉布氏自由能G,不過知不知道也不影響解題...
-△h = RTlnX1 = △G = G(in liquid solution)-G(pure gas)
lnX1為負值
所以-△h為負值
因此△h必為正值
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