作者mdpming (+ 我不是豬 +)
看板Grad-ProbAsk
標題[理工] [工數]- Fourier
時間Sun Nov 8 21:19:15 2009
1.
Find complex Fouier series of f(x)
2
f(x+2)=f(x) and f(x) = x + x in 0 < x < 1
2
f(x) = x - x + 2 in 1 < x < 2
=
答案是
11 8 2i 1 n inπx
f(x) = ---- + M [ ----- + -------(1 + (-1) ]e
6 n=-8 nπ 2 2
n=/=0 n π
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推 CRAZYAWIND:分段積 加做苦工積分而已 11/08 21:29
推 IMISSA:應該直接積就可以了 11/08 21:51
推 jmKevin:這題要有耐心的慢慢積= = 11/09 07:27
→ mdpming:是喔...好吧`~"~ 11/09 09:33
→ iyenn:不難積呀XD 11/09 19:57