(x^2-1)y''+xy'-y=0
級數解在整理係數時
(2n-3)(2n-5)....5x3x1 (2n-2)!
a2n= - ______________________ = - _______________________
(2n)(2n-2)......6x4x2 (2^2n-1)n!(n-1)!
↑2n表偶數
↑ 書直接寫成這樣
請問怎整理成這樣的= =?
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