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※ 引述《lionichiro (阿暐~~!)》之銘言: : Consider a potential given by U(x)={∞, x<a ; -V, 0<x<a ; 0, x>a} with V>0 : Assume a plane wave of momentum -k(h/2π) is sent from +∞ : Please find the amplitude of reflect wave? U(x)={∞, x<0 ; -V, 0<x<a ; 0, x>a} (h/2π我用Η表示@@) Ⅰ 0 Ⅱ a Ⅲ _____________________________________________________________________ ik3x -ik3x ψ1 = 0 ψ2 =Acos(k2x)+Bsin(k2x) ψ3 = Cexp + Dexp __________ √(kΗ)^2 +V k2=____________ k3 = -k Η 令入射波C = 1 B.C. ψ1(0) =ψ2(0) => A=0 ika -ika ψ2(a) =ψ3(a) , Bsin(k2a) = exp + Dexp __________(1) ika -ika ψ'2(a)=ψ'3(a), Bk2*cos(k2a) = ik*exp - Dik*exp ________(2) i2ka (1)/(2) 再整理一下可得 exp [ik*tan(k2a) - k2] D = ____________________ k2 + ik*tan(k2a) * v3*D D * R = ________ = D *D = 1 * v3*A A 如果他只給兩分就直接寫x<0位能∞所以沒有穿透,穿透係數=0,反射係數=1 有錯誤請多指教.@@ : 拜託了!! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.171.100.66 ※ 編輯: kagato 來自: 118.171.100.66 (12/08 22:10)
gogogoclark:嗯?(1)式後面應該是D*exp(ika) 12/08 22:57
kagato:把k都改k3好了~_~ 謝謝指正 12/08 23:00
gogogoclark:若令k=k3 那就要改成令D=1 求C了 12/08 23:16
gogogoclark:最後反射係數之分母要換成(c*)*c 12/08 23:28
youmehim:k2裡面的V少乘了2m 12/09 10:46