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※ 引述《GI9 ( )》之銘言: : [a+b ab 0 0] : [ 1 a+b ab 0] : [ 0 1 a+b ab] : [ 0 0 1 a+b] : =M : Show that if a and b are real numbers , which are not both zero , : then M is invertible A4=|M| A3=|a+b ab 0 | | 1 a+b ab | | 0 1 a+b| A2=|a+b ab| | 1 a+b| A1=a+b A2=(a+b)^2-ab An=(a+b)An-1-abAn-2 r^2-(a+b)r+ab=0 (r-b)(r-a)=0 if a=/=b An=c1a^n+c2b^n A1=a+b=c1a+c2b A2=a^2+ab+b^2=c1a^2+c2b^2 ,a^2+ab+b^2=c1a^2+c2b^2 a^2+ab =c1a^2+c2ab ab+b^2=c1ab+c2b^2 -------------------------- ,------------------------ b^2=c2(b^2-ab) a^2=c1(a^2-ab) c2=b/(b-a) c1=a/(a-b) 1 1 An=-----a^n+1 + -----b^n+1 a-b b-a If a=b An=c1na^n+c2a^n A1=2a = c1a +c2a A2=3a^2=2c1a^2 +c2a^2 c1+c2=2 2c1+c2=3 c1=1 c2=1 An=(n+1)a^n =>for a=/=b, 1 1 An=-----a^n+1 + -----b^n+1 a-b b-a for a=b , An=(n+1)a^n => a=b case ,ab=/=0 det不為零 a=/=b case,a^n+1-b^n+1=0 det為零 for n=4 a^5-b^5=0 a=be^i2nπ/5 n=0,1,2,3,4 a=b不合 其它的都是複數根了 不過感覺怪怪的XD,是這樣嘛?= = -- 為者常成.行者常至 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 123.193.214.165
GI9:我不知道 我也沒有正確解答... 12/17 14:57
GI9:不過還是謝謝了!! 12/17 14:59
iyenn:誰來用電腦跑看看-,- 12/17 15:09