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In a personal computer, the optical drive has a rotation speed 7500 rpm, a 40000000 bytes/second transfer rate, and a 60 ms seek time. The drive is serve with a 16MHz bus, which is 16-bit wide. When trsnsferring the 100000-byte data, what is the bottleneck? 我的算法是 100000/16*10^6 但是張帆給的答案是 (100000/2)/16*10^6,請問為什麼他要先除以2呢? 感謝指教~~ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.135.41.17
killerjoe:我會直接算16M 次/sec*16 bit/次 = 32M Byte/sec 12/25 23:31
killerjoe:再算optical的速度 12/25 23:32
killerjoe:較慢者為bottleneck 12/25 23:32
assassin88:似乎也可行~那請問你算出的結果是? 12/26 15:51