A bowl contain two red balls,two white balls,and two ball that are either red
or white.Let p denote the probability of drawing a red ball from the bowl.
We shall test the null hypothesis Ho:p=1/2 against the alternative hypothesis
Ha:p≠1/2. Draw 4 balls at random from the bowl one at time and with replace.
Let x denote the number of red balls drawn.
求拒絕域?
Ans: c:{x=0,4}
我想問的是為什麼拒絕域會是0和4？
如果把題目改成兩紅球,兩白球和一顆不是紅就是白,Ho:p=3/5,Ha:p=2/5,其他都不變
拒絕域又會是多少？
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