Consider a logical address of 2048 pages of 1024 words (4byte) each,
mapped onto a physical of 64 frames. Assume the smallest memory
allocation unit is one byte
a. How many bits in the logical and physical address
b. one-level page table is used, how many bytes are required by PT
c. two-level PT is used, and first level table has 32 entries,
what is the minimal amount of memory required by PT.
可以幫我算一下嗎?(以及列式)
另外題目有點看不懂,是說總共2048個page?
每個page有1024個word? 那(4byte)又是指什麼?
謝謝
--
◢██████◤◢██◤ ◢◥◣ ◥████◣
◢▇█████◤◢██◤ ◢█/▇◥◣ ◥███▇◣
◢██▁▁▁▁▁█ ███ ◤ ◥██◣◥█◣/█◤██◣ ██████◣
◢▇▇▉█████▏◢███◤ ◥██◣◥▇█◤◢███ ██◣▏█▇▇◣
▇▇▇▉█▉◤ █▏███ ◤ ◥ ███ ██◢◣███◣█▇▇◣████
▇▇▇█◤ █◤███◤ ◥███◥██████████████
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 122.116.14.2