看板 Grad-ProbAsk 關於我們 聯絡資訊
※ 引述《chihhungw (衝浪 八呎板)》之銘言: : y^-x^/(x^+y^)^ : 對y積分 : 答案是-y/x^+y^ +g(x) : 感激不盡 ∫(y^2 - x^2)dy/(x^2+y^2)^2 y/x = u = (1/x)∫(u^2-1)du/(u^2+1)^2 = (1/x)∫(1-u^(-2))du/(u+u^(-1))^2 k = u + 1/u = (1/x) [-u/(u^2+1)] = (x) [-y/x/(y^2+x^2)] = -y/(y^2+x^2) 再加上積分常數 g(x)即可 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 122.124.103.134