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L{(cos t)u(t-π/2)}=L{-(sin(t-π/2)u(t-π/2)} | | |_____________________| | | 為什麼第二步不是 L{cos(t-π/2)u(t-π/2)} 除了尤拉判斷以外.他的判斷依據又可以是什麼?! 如果變成L{(cos t)u(t-3π/2)}=L{(_____(t-3π/2))u(t-3π/2)} 或者L{(sin t)u(t-π/2)}=L{(_____(t-π/2))u(t-π/2)} -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.166.180.125
smallprawn:ㄜ..是我問的太奇怪嗎= =.. 01/24 14:44