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2 -1 s + 1 L [ln----------] 2 (s - 1) 答案 2 t ---(e - cost) t 幫我檢查哪裡錯... 2 1 -1 d s + 1 - --- L [ --- ln ------- ] t ds 2 (s-1) 2 1 -1 s - 2s +1 = - --- L [ ----------- ] t 2 s + 1 2 1 -1 s -1 s -1 1 = - --- { L [ ------- ] - 2 L [ ------- ] + L [ -------- ] t 2 2 2 s + 1 s + 1 s + 1 1 d -1 s = - ---[ --- L [ ------- ] - 2cost + sint ] t dt 2 s + 1 1 = - ---[-2cost] .............................. t -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.32.91.86
shinyhaung:第二行微分就錯了 最好拆成ln相減再微 02/05 13:55
CRAZYAWIND:錯~~~很~~~大~~~ 02/05 13:59
CRAZYAWIND:先拆成-1/t L^-1 d/ds [ln s^2+1 -ln s^2-2s+1] 02/05 14:00
t5d:ln微分不單單變倒數而已 內部的項還要再對x微分一次 02/05 14:11
mdpming:痾... 02/05 15:34