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Consider a 6000rpm disk, which is of one single head, 11tracks, and 110sectors in total. Let the seek time is linearly proportional to the number of track traveled, and to move the head across one track takes 1ms. Suppose that the current head position is at track 0, sector 0. It takes ____ ms to seek to track 10, sector 5. (note that tracks and sectors are numbered from 0) 手邊的解答: disk有6000rpm => 轉一圈需0.01sec 又一track 有10 sectors 所以轉動一圈需0.001sec 故disk head由track 0移動到track 10需10*0.01sec=100ms disk head由sector 0 移動到sector 5 需5*0.001sec=5ms 所以需100+5=105ms 問題: 請問一下它為什麼不需要加translate time(1/2*60*1/6000) ?? 麻煩幫我解答一下 感謝!! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.27.3.226
EntHeEnd:他問seek time而已 02/26 16:15
luckyburgess:噗 對後 我沒看清楚題意 謝啦!! 02/26 16:30
bensome0624:為何由track 0至track 10不是1ms*10而是用轉一圈的 02/26 17:27
bensome0624:時間當作trackr間移動的時間呢? 02/26 17:27
killersky:你的這份解答有錯 12/21 14:38