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※ 引述《usa0204got (便秘)》之銘言: : _ _ _ : if F = (x-y)/(x^2+y^2)i+(x+y)/(x^2+y^2)j is a defined in a simply : connected domain R. evaluate the integral : _ _ : ∫F‧dr : c : along the path r=2+(4Θ/5π) from (x1,y1)=(2,0) : to (x2,y2)=(0,4),where r and Θ are polar coordinates . : 卡在積分 感謝幫忙 Curl F = 0 (x-y)/(x^2+y^2) 對x偏積 => ψ1(x,y) = 0.5 ln│x^2 + y^2│ - arctan(x/y) + g(y) (x+y)/(x^2+y^2) 對y偏積 => ψ2(x,y) = 0.5 ln│x^2 + y^2│ + arctan(y/x) + f(x) ∴ ψ(x,y) = 0.5 ln│x^2 + y^2│ + arctan(y/x) - arctan(x/y) + c = 0.5 ln│x^2 + y^2│ + π/2 - 2arctan(x/y) + c 不知有沒有錯,大家討論一下 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 59.125.52.40
shinyhaung:與路徑無關 直接帶頭尾 常數不用吧 03/08 16:52
thefirst:積完有C 起點終點座標帶入 C自然消掉 03/08 17:14
zeowo:標題錯誤 03/09 10:46