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題目: find the solution of the equation [ e^xsiny - 2x ]dx + [ e^xcosy + 1 ]dy = 0 siny de^x - e^x dsiny -2x dx + dy = 0 d(-e^x siny) - 2xdx +dy = 0 y = c + x^2 + e^xsiny 沒解答~ 請問這樣算對嗎? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 125.228.236.166
kagato:e^xsiny -x^2 + y = c 03/11 20:51
shinyhaung:d(e^x siny)是正的吧 03/11 20:51
kagato:這有點明顯正和= =+ 03/11 20:51
mdpming:恩 同2樓.. 03/11 20:55
topee:cos -> -sin 不是等於負的嗎? 03/11 20:56
mdpming:那是微分 ... 03/11 20:56
mdpming:你現在是積分... 03/11 20:57
ricky764:dsinx = cosx dx 03/11 20:57
topee:那 sin 積分等於 ?? 03/11 20:59
shinyhaung:sin 積分等於 -cos 03/11 21:01
topee:我搞混了... 感謝... 03/11 21:02
squallting:把你算的答案全微分 看會不會回到第一行就知道對不對了 03/11 21:09