2sinx -π≦x＜-π/2
6 x=-π/2
f(x)=｛ x^2 -π/2< x < 0 ｝
3cosx 0≦x＜π/2
6x π/2≦ x ≦π
求下列收斂值?
(a)x=-π/2
(b)x= 0
(c)x= π/6
(d)x= π
感激不盡~~
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