推 shinyhaung:有答案嗎? I1(x) = -K1x ?? 03/18 11:32
→ ricky764:沒答案..冏 I1 I2 是X的函數 03/18 11:44
dI1(x)
──── = -K1 I1(x) I2(x)
d x
dI2(x)
──── = K2 I1(x) I2(x) where K1 K2 is constant
d x
I1(x) I2(x) I1(0) I2(0)
Boundary Condition : ─── + ─── = ─── + ─── = 1
K1 K2 K1 K2
solve I1 I2 .
中央光電96第二題...
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