→ ericabab:你把解代回去不就知道對不對了... 03/19 01:53
→ gn00618777:冏" 03/19 07:44
沒有解答，想問看看是不是有人跟我解一樣
'
y1 =3y1+4y2
y2' =3y1+4y2
with Y(0)=[y1(0)] = [6]
[y2(0)] [1]
我求出來c1= -5/7
c2= 22/7
y= [-4c1+c2e^7t]
[3c1 +c2e^7t]
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