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Solve the system of differential equations as follow dx/dt=4x-2y dy/dt=x+y x(0)=6 y(0)=3 ------------------------------------------------------ Dx-4x=-2y . x(D-4)=-2y .......(1) Dy-y=x . y(D-1)=x ...........(2) y(D-1)(D-4)=-2y y(D-2)(D-3)=0 , y(t) = c1e^2t+c2e^3t 之後就卡住了= =......... -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 124.12.50.85
squallting:先用y(0)=3求出c1c2 然後將y帶回dy/dt=x+y求x 03/26 14:50
squallting:然後再用x(0)=6找出c1c2 最後再求出c1c2的值就ok了 03/26 14:51
bob198817:你的寫法會被扣分 D是有看順序的 只是常系數可以亂調換 03/26 15:34
bob198817:而且你也應該把微分運算子寫再變數之前! 03/26 15:35