[2xy+(2y^2)]dx+(x^2+4xy)dy=0
[sol]:
2xydx+2y^2dx+x^2dy+4xydy=0
(2xydx+x^2dy)+(2y^2dx+4xydy)=0
x(2ydx+xdy)+2y(ydx+2xdy)=0
x*[d(x^2*y)/x]+2y*[d(x*y^2)/y]=0
d(x^2*y)+2*d(x*y^2)=0
積分=>
得通解:x^2y+2xy^2=c
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