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y'-y = y^2 dy-ydx=y^2dx 除y^2 y^-2dy - y^-1dx = dx 令u= y^1-2 =y^-1 du = (1-2)y^-2dy -du-udx = dx du+udx = -dx (D+1)u = -1 u = c1e^-x h u = (1-D)(-1) p = -1 1/y = c1e^-x-1 y=(c1e^-x-1)^-1 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 125.228.230.228
WinAVI:這題不用白努力 直接分離變數就可以囉 04/07 20:47
topee:題目好像有給指定 04/07 20:54