→ kagato:L^-1{1/(s+2)^2} = t*exp^(-2t),多練一點就很熟了=.= 04/09 01:33
→ iamwwj:謝謝kagato大指導! 04/09 01:39
y'+2y=e^-2t ,y(0)=1
--------------------------------
￡[y'+2y] = 1/s+2
sy'(s) - y(0) + 2y(s) = 1/s+2
(s+2)y(s) = 1/s+2 + y(0)
y(s) = 1/(s+2)^2 + 1/s+2
￡^-1[y(s)] = ￡^-1[ 1/s^2+4s+4 + 1/s+2]
接下來該怎麼做呢@@??
麻煩指導一下謝謝
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