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' x(t) = [0 1]x(t) + [0]u(t) [-1 0] [1] y(t) = [0 1]x(t) If u(t)=0 , x(0) = [ 1] , find x(π/2) [-1] 只是想問初值要怎麼代= =" 沒做過這種題目 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.171.195.28
honestonly:取拉式轉換 SX-x(0) = X ,X(s) = (SI-A)^-1 x(0) 04/10 12:33
honestonly:反拉式 可得x(t) 然後帶入t=π/2 04/10 12:34
honestonly:少打一個A ,SX-x(0)=AX 04/10 12:46