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※ 引述《mama0425 (Marvelous)》之銘言: : 大家好~ : 我有算出幾題機率分配的問題,但不太確定算得對不對,所以可否請版上神人幫我看看^^ : 1. A random variable Y has the probability density function : e^(-y) , y > 0 : f(y) = : 0 , else : Find E[e^(0.5y)]. ∞ 0.5y -y ∞ -0.5y -0.5y ∞ E[e^(0.5y)]=∫ e * e dy = ∫ e dy = -2e │ = 2 0 0 0 答對了XD : A) 1 B) 1/2 C) 0 D) 2 這題我是算:(D) : 2. Let the joint p.d.f. of x and y be : 4xy , 0 < X < 1, 0 < Y < 1 : f(x,y) = : 0 , else : Find P(X < 1/2│Y > 3/4) : A)5/8 B)1/8 C)1/4 D)3/8 這題我是算:(C) 1 2 1 f (y)=∫4xy dx = 2y*(x )│= 2y Y 0 0 P(X < 1/2且Y > 3/4) (7/64) P(X < 1/2│Y > 3/4) = ───────── = ─── = 1/4 P(Y > 3/4) (7/16) 1/2 1 1/2 2 1 P(X < 1/2且Y > 3/4)=∫ ∫ 4xy dy dx = ∫ 2x*(y )│ dx 0 3/4 0 3/4 1/2 2 1/2 =∫ (7/8)x dx = (7/16)x │ = 7/64 0 0 也對囉XD 1 2 1 P(Y > 3/4)=∫ 2y dy = y │ = 7/16 3/4 3/4 : 3. Let Y denote an exponential random variable with mean 2. : F(Y>4│Y>2). ^^P? : A) e^(-1) B) e^(-2) C) e^(-4) D) 1-e^(-2) 這題我是算:(A) E(X)=1/λ=2 所以λ=1/2 -2 P(Y>4∩Y>2) P(Y>4) 1-F(4) e -1 P(Y>4│Y>2) = ───── = ─── = ─── = ── = e P(Y>2) P(Y>2) 1-F(2) -1 e 還是答對囉^^ x (-1/2)t (-1/2)t x (-1/2)x F(x)=∫(1/2)e dt = -e │ = 1-e 0 0 : 麻煩大家幫我看看是否正確,謝謝 <(_ _)> 恭喜都對嚕^^ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 125.231.99.236
mama0425:y大真的很謝謝你(鞠躬),而且還列出算式出來給我, 感謝:) 04/10 16:24