推 shinyhaung:分部積分 u=lnx,dv=x^2dx 故 du=(1/x)dx,v=(1/3)x^3 04/12 23:39
→ funtsung:lnx d (1/3 x^3) = udv = uv - Svdu 04/12 23:39
→ shinyhaung: uv-∫vdu = (1/3)x^3(lnx)-∫(1/3)x^3(1/x)dx 04/12 23:40
→ shinyhaung: = (1/3)x^3(lnx) - (1/9)x^3 04/12 23:40
推 zeowo:標題錯誤 04/13 21:36