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題目是 There are eight people, denoted A,B,....,H be seated about the square table, and two of the eight people, say A and B, do not get along well, how many different seatings are possible with A and B not sitting next to each other ? 課本的答案是: 8!/4 - (2*6! + 2*6!) = 7200 ; 坐在同一側跟坐在桌腳兩側都算進去了 可是我想法是: 8!/4 - (6!/2 + 6!/2) = 9360 ; 因為是方桌所以我都除以四 請問是我的想法錯還是課本解答錯? 麻煩可以幫我解惑一下嗎... 感激不盡 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.170.207.131