→ honestonly:一階線性 06/16 13:32
Solve the initial value problem by Laplace transformation.
y''+4ty'-4y = 0 ; y(0)=0, y'(0)=5.
以下是我的算法
sol:
L{y'} = sY-y(0) = sY
L{y''} = s^2 Y - sy(0) - y'(0)
= s^2 Y - 5
- d ┌ ┐
L{ty'} = ----│s^2 Y - sy(0) - y'(0) │
ds └ ┘
-d ┌ ┐
= ----│s^2 Y -5 │
ds └ ┘
=-sY - s^2 Y'
s^2 Y - 8s Y - 4s^2 Y' -4sY =0
=> 4s^2 Y'+ (12s-s^2)Y = -5
(12s-s^2) -5
=> Y' + ----------- Y = ------
4s^2 4s^2
再來後面解不太出來...
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